Andrelon Classic anti-roos shampoo
Groceries · compared per litre · 1 places with a price
Provisional entity
Unconfirmed entityNobody has corroborated that Andrelon Classic anti-roos shampoo is a distinct thing rather than another name for something already here. Adding a price is what promotes it; finding its duplicate is what removes it.Look for duplicatesAdd a price
Current price, comparison unit
7.230EUR / L
· measured at the Shelf
7.230 – 7.230observed range across all recorded places
Stale · 26 Feb 2025checkjebon Dutch supermarket prices12 reports
based on 12 reports:12 checkjebon Dutch supermarket prices
n=12 · 1 seller · 1 source · since 7 Feb 2023
Price history
Coop (chain-wide, NL) · currently the cheapest recordedWhere it is priced
ranked by unit priceshowing 1 of 1| Place | per L | Tax | Market | Basis | Freshness |
|---|---|---|---|---|---|
| Coop (chain-wide, NL) Coop · NL | 7.230 | incl. VAT | public | Shelf | 26 Feb 2025 |
n=1 · 1 seller · since 7 Feb 2023
Observations
newest firstshowing 12 of 12| Observed | Contributor | Where | per L | Evidence | Actions |
|---|---|---|---|---|---|
| 26 Feb 2025 | checkjebon Dutch supermarket prices | 7.230 | bare claim | ||
| 21 Feb 2025 | checkjebon Dutch supermarket prices | 3.350 | bare claim | ||
| 23 Sept 2024 | checkjebon Dutch supermarket prices | 7.230 | bare claim | ||
| 16 Sept 2024 | checkjebon Dutch supermarket prices | 3.330 | bare claim | ||
| 10 May 2024 | checkjebon Dutch supermarket prices | 7.230 | bare claim | ||
| 7 May 2024 | checkjebon Dutch supermarket prices | 6.810 | bare claim | ||
| 30 Apr 2024 | checkjebon Dutch supermarket prices | 3.390 | bare claim | ||
| 26 Feb 2024 | checkjebon Dutch supermarket prices | 6.810 | bare claim | ||
| 19 Feb 2024 | checkjebon Dutch supermarket prices | 3.390 | bare claim | ||
| 6 Oct 2023 | checkjebon Dutch supermarket prices | 6.810 | bare claim | ||
| 7 Jul 2023 | checkjebon Dutch supermarket prices | 6.890 | bare claim | ||
| 7 Feb 2023 | checkjebon Dutch supermarket prices | 6.150 | bare claim |
n=12